README.md

1185. Day of the Week

Given a date, return the corresponding day of the week for that date.

The input is given as three integers representing the day, month and year respectively.

Return the answer as one of the following values {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}.

Example 1:

Input: day = 31, month = 8, year = 2019 Output: "Saturday" 

Example 2:

Input: day = 18, month = 7, year = 1999 Output: "Sunday" 

Example 3:

Input: day = 15, month = 8, year = 1993 Output: "Sunday" 

Constraints:

• The given dates are valid dates between the years 1971 and 2100.

Solutions (Rust)

1. Solution

implSolution{pubfnday_of_the_week(day:i32,month:i32,year:i32) -> String{letmut day = day;letmut months = [0,31,59,90,120,151,181,212,243,273,304,334];let week = ["Thursday","Friday","Saturday","Sunday","Monday","Tuesday","Wednesday"]; day += (year - 1971)*365 + (year - 1969) / 4 + months[month asusize - 1];if year % 4 == 0 && month > 2{ day += 1;} week[day asusize % 7].to_string()}}